# Line slope calculator 8x-5y=40

**Straight line given by points A[5; 0] and B[10; 8]**

## Calculation:

**Slope-intercept form of line:**y = 1.6x-8

**Canonical form of the line equation:**8x-5y-40 = 0

**Parametric form of the line equation:**

x = 5t+5

y = 8t ; t ∈ R

**Slope:**m = 1.6

**Slope angle of line: φ =**57°59'41″ = 1.0122 rad

**X intercept:**x

_{0}= 5

**Y intercept:**y

_{0}= q = -8

**Distance line from the origin:**d

_{0}= 4.24

**The length of the segment AB: |AB| =**9.434

**Vector: AB =**(5; 8)

**Normal vector: n =**(8; -5)

**Midpoint of the segment AB: M =**[7.5; 4]

**Perpendicular Bisector equation:**5x+8y-69.5 = 0

**Vector OA = (5; 0) ; |OA| = 5**

**Vector OB = (10; 8) ; |OB| = 12.8062**

**Scalar product OA .OB = 50**

**Angle ∠ AOB = 38°39'35″ = 0.6747 rad**